Asample data set has a mean of 122.3 and a standard deviation of 18.5. convert a score of 168.4 to a z score and determine if the score is “usual” or “unusual.”

and this Z-score is “unusual.”

Step-by-step explanation:

To calculate the Z score use the following formula

Where

μ is the average

is the standard deviation

x is the data to which we will calculate the z-score

In this case

So

A z-score is unusual if or

Finally

and this Z-score is “unusual.”

x/7.50 = 15

x= 7.50 / 15 divide

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )