Arectangles length is 1.5 times its width. the perimeter of the rectangle is four more than 3 times the length. what are the dimensions of the rectangle

  8 by 12 units

Step-by-step explanation:

Let w represent the width of the rectangle. Then the length is 1.5w. The perimeter is 4 more than 3 times this, so is (3(1.5w) +4) = 4.5w+4

The perimeter is given by the formula ...

  P = 2(length + width)

Filling in the given values for the variables, we have ...

  4.5w +4 = 2(w +1.5w)

  4 = 0.5w . . . . . . subtract 4.5w and collect terms

  8 = w . . . . . . . . . multiply by 2

  length = 1.5×8 = 12

The rectangle is 8 units wide and 12 units long. The perimeter is 40 units.

horizontal translation of 2 units in the positive x direction

followed by

vertical translation of 3 units in the positive y direction

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42