If m∠a = (3x-6)° and m∠b = (x + 9)°, find the m∠d. a) 32° b) 39° c) 41° d) 49° e) none of the above

Because line BD goes through the center of the circle Angle A is a right angle which equals 90 degrees.

Set the equation for A to equal 90 and solve for x:

3x-6 = 90

Add 6 to each side:

3x = 96

Divide both sides by 3:

x = 32

Now we have a value for x , use that to solve for angle b:

B = x +9 = 32 + 9 = 41 degrees.

Now we know A and B, we can solve for D.

The three inside angles of a triangle need to equal 180.

D = 180 - 90 - 41 = 49 degrees.

The answer is D) 49

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

2x^2+5x+17

your welcome. : )