Nina made two investments: investment a has a value of $50 at the end of the first year and increases by 8% per year. investment b has a value of 60$ at the end of the first year and increases by 3$ per year. nina checks the value of her investments once a year, at the end of the year. what is the first year in which nina sees that investment a's value exceeded investment b's value?

5/12, or 5: 12

step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

sure i'm up for it

step-by-step explanation: