Agolf ball is dropped onto concrete from 2 meters up. each time it bounces, it rebounds to 2/3 of its previous height. on the sixth rebound, how much will it rise

Step-by-step explanation:

The ratio is the same each time (2/3), so this can be modeled as a geometric sequence.

an = a₁ (r)^(n-1)

where an is the nth term, a₁ is the first term, and r is the common ratio.

On the first rebound, the ball rises to 2/3 × 2 = 4/3, so a₁ = 4/3.

an = 4/3 (2/3)^(n-1)

On the sixth rebound, the ball rises to:

a₆ = 4/3 (2/3)^(6-1)

a₆ = 4/3 (32/243)

a₆ = 128/729

a₆ ≈ 0.176

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !