An exercise class has two options a $25 pass for all sessions during the month or $3 per lesson write an equation to model the cost of going to the exercise class for a month using a pass and another equation for paying a fee for each lesson

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Step-by-step explanation:

Given : An exercise class has two options a $25 pass for all sessions during the month or $3 per lesson

To Find: write an equation to model the cost of going to the exercise class for a month using a pass and another equation for paying a fee for each lesson.

Solution:

Let the total cost be y

Option 1) a $25 pass for all sessions during the month

So, equation for option 1 :

Option 2) $3 per lesson

Let x be the number of lessons

So, cost of x lessons = 3x

So, Total cost:

So, equation for option 2 :

Hence an equation to model the cost of going to the exercise class for a month using a pass and another equation for paying a fee for each lesson is and

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: