At which values of x does the function f(x) have a vertical asymptote? check all that apply

The values of x are -6 , 0 , 1 ⇒ Answers C , D , E

Step-by-step explanation:

* Let revise how to find the vertical asymptote

- Vertical asymptotes of a rational function f(x)/g(x) can be found by

 solving the equation g(x) = 0 ⇒ the denominator of the fraction

- Note: this only applies if the numerator f(x) is not zero for the same

 x value

* Lets solve the problem

∵ F(x) = 1/x(x + 6)(x - 1)

∵ The denominator of the fraction is x(x + 6)(x - 1)

- To find the equation of the vertical asymptote Put the

 denominator = 0

∴ x(x + 6)(x - 1) = 0

- The denominator has three factors, equate each by 0

∴ x = 0

OR

∴ x + 6 = 0 ⇒ subtract 6 from both sides

∴ x = -6

OR

x - 1 = 0 ⇒ add 1 to both sides

∴ x = 1

∴ From all above there are 3 vertical asymptotes at x = -6 , 0 , 1

* The answers are C, D , E

step-by-step explanation:

idk the answer i want to say 10 but then it would be equal so try 9 but then yeah so yeah we love edgen

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol