Show that square of any positive integer can not be of form 7q + 3 or 7q+5or 7q + 6, for any integer q

Step-by-step explanation:

7q + 3 or 7q+5 or 7q + 6

solve for q

7q + 3 =

7q + 3 -3 =-3

7q = -3

7q/7 = -3/7

q = -3/7

7q + 3 =

7q + 6 -6 =-6

7q = -6

7q/7 = -6/7

q = -6/7

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9