Which absolute value function, when graphed, will be narrower than the graph of the parent function, f(x) = |x|? f(x) = |x| – 3 f(x) = |x + 2| f(x) = 0.5|x| f(x) = 4|x|

f(x) = 4|x|

Step-by-step explanation:

the graph of f(x) = |x|, looks like a "V"

if we want to make the graph "narrower", what we are doing is really trying to make the slope steeper (i.e more vertical) so that the opening of graph at the top of the "V" becomes smaller.

in order the make the slope steeper, we have to multiply the x-term of the function (in this case |x|) by any factor that is greater than 1. (multiplying by factors smaller than 1 will make the slope more gentle and hence making the "V" wider).

The only choice that shows the original function multiplied by a number that is greater than 1 is f(x) = 4|x|

the answer is 62

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt