What is the answer to 8(s^2+2s+3)+(2s+s+1)

s = (i sqrt(439))/16 - 19/16 or s = -(i sqrt(439))/16 - 19/16

Step-by-step explanation:

Solve for s:

1 + 3 s + 8 (s^2 + 2 s + 3) = 0

Expand out terms of the left hand side:

8 s^2 + 19 s + 25 = 0

Divide both sides by 8:

s^2 + (19 s)/8 + 25/8 = 0

Subtract 25/8 from both sides:

s^2 + (19 s)/8 = -25/8

Add 361/256 to both sides:

s^2 + (19 s)/8 + 361/256 = -439/256

Write the left hand side as a square:

(s + 19/16)^2 = -439/256

Take the square root of both sides:

s + 19/16 = (i sqrt(439))/16 or s + 19/16 = -(i sqrt(439))/16

Subtract 19/16 from both sides:

s = (i sqrt(439))/16 - 19/16 or s + 19/16 = -(i sqrt(439))/16

Subtract 19/16 from both sides:

 s = (i sqrt(439))/16 - 19/16 or s = -(i sqrt(439))/16 - 19/16

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step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl