Positive integer a has 2 different prime factors: p and q (p< q) such that a = pq. positive integer b is greater than a and the quotient a^2/b is an integer. how many possible values of b are there? give an explanation with your answer!

4

Step-by-step explanation:

The integer A^2 will have 9 divisors:

1, p, q, p^2, pq, q^2, p^2q, pq^2, p^2q^2

Of these, the last 4 are greater than A. Hence there will be these 4 values of B.

i dont know

step-by-step explanation:

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.