Find the given higher-order derivative. f''(x) = 9- 3/x f'''(x)=

Step-by-step explanation:

We are given with Second-order derivative of function f(x).

We need to find Third-order derivative of the function f(x).

We know that,

f'''(x) = (f''(x))'

So,

Therefore,

answer: i don't understand. what are the options

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.