Find the cube roots of 8i. write the answer in a + bi

1 Answers. #1. +1. We have that. a0 = ∛8 [ cos [ (pi/2)/3] + i *sin [(pi/2)/3 ] = ∛8 [ cos [ (pi/6)] + i *sin [(pi/6) ] = 2 [ √3/2 + 1/2 * i ] = √3 + 1i. a1 = ∛8 [ cos ( (pi/2)/3 + 2pi/3 ) + i sin ( (pi/2 )/3 + 2pi/3 ) ] = 2 [ cos (5pi/6) + i sin (5pi/6) ] = 2 [ - √3/2 + (1/2)*i ] = - √3 +1i. ...

idk

step-by-step explanation:

add the numbers under frequency to find the total number:

5 + 8 +7 + 4 + 0 +1 = 25

the answer is 25.