Find a number that has 4 identical even factors each factor must be greater than one and can have only one and itself as factors

The Number is 16.

Step-by-step explanation:

Given: Number has 4 Factors.

           All 4 factors are same and even.

           Factor are greater than 12.

           Factors can only has 2 factors that is 1 and itself or we can say factors are prime no.

We need to find this number.

We know that there is only 1 number which is even prime.

So, our required factor is 2.

And required Number = 2 × 2 × 2 × 2 = 16

Therefore, The Number is 16.

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer