The length of time it takes to find a parking space at 9 a. m. follows a normal distribution with a mean of 5 minutes and a standard deviation of 2 minutes. find the probability that it takes at least 8 minutes to find a parking space. (round your answer to four decimal places.)

0.0668

Step-by-step explanation:

Given: Mean :

Standard deviation :

The formula to calculate z is given by :-

To check the probability it takes at least 8 minutes (X≥ 8) to find a parking space.

Put X= 8 minutes

The P Value =

Hence, the probability that it takes at least 8 minutes to find a parking space = 0.0668

The probability that it takes atleast 8 minutes to find a parking space is 0.0668

Given the Parameters :

First we find the Zscore :

Zscore = (8 - 5) / 2 = 1.5

The probability of taking atleast 8 minutes can be expressed thus and calculated using the normal distribution table :

P(Z ≥ 1.5) = 1 - P(Z ≤ 1.5)

P(Z ≥ 1.5) = 1 - 0.9332

P(Z ≥ 1.5) = 0.0668

Therefore, the probability, P(Z ≥ 1.5) is 0.0668

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let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

the answer is a) y= 2 csc [0.5 (x+pi/2)]-1

step-by-step explanation: