An equation in slope-intersept form the lines that passes thought (-8,1) and is perpindicular to the y=2x-17.

y = (-1/2)x -3

Step-by-step explanation:

We are given

y = 2x-17

which is in slope-intercept form: y = mx +b

Where m is the slope. so, m= 2

But this is perpendicular, When a line is perpendicular then the slope become -1/m so in our case the slope m will be = -1/2

Using the point(-8,1) we can find the b i.e the y intercept

We have x = -8, y =1 and m=-1/2

y = mx + b

1 = (-1/2)(-8) + b

1 = 4 + b

=> b = 1-4

b = -3

The equation of slope intercept form will be

y = mx + b

Putting value of m= -1/2 and b = -3

y = (-1/2)x -3

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answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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