Acircular garden with radius of 8 feet is surrounded by a circular path with a width of 3 feet. what is the approximate area of the path alone? use 3.14 for π

The area of the path is 178.98 feet²

Step-by-step explanation:

* lets study the information in the problem

- The radius of the circular garden is 8 feet

- The width of the surrounded path is 3 feet

- We have two concentric circle, the inside one is the garden and the

 outside one the the garden with the path

- The radius of the inside circle is 8 feet

- The radius of the outside circle is 8 + 3 = 11 feet

- The area of the bath is the difference between the area of the

  two circles

* Lets solve the problem

∵ The area of the circle = π r²

∵ π = 3.14

- Lets find the area of the inside circle

∵ Its radius = 8 feet

∴ Its area = 3.14 (8)² = 200.96 feet²

- Lets find the area of the outside circle

∵ Its radius = 11 feet

∴ Its area = 3.14 (11)² = 379.94 feet²

- Lets find the difference between their areas

∵ The difference between their areas = area outside - area inside

∴ The difference = 379.94 - 200.96 = 178.98 feet²

- The area of the path = the difference of their areas

∴ The area of the path is 178.98 feet²

i believe that the slope of the line is -5

step-by-step explanation:

can you post the graph?