How many zeros does the function f(x)=4x3-x2+1 have

3

Step-by-step explanation:

The Fundamental Theorem of Algebra states that a polynomial of degree n has n zeros. there may be complex zeros

4x³ - x² + 1 ← is a polynomial of degree 3, thus has 3 zeros

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~