Triangle abc is reflected over the line y=x triangle abc has points (-6,-,-1) and (-5,-6) what is the c coordinate

C' = (-6, -5)

Step-by-step explanation:

We are given that a triangle ABC is reflected over the line y = x.

Given the points of the vertices of the triangle ABC to be (-6, -1) (-2, -1) and (-5, -6) respectively, we are to determine the coordinates of C'.

When reflected over the line y = x, the x and y coordinates exchange their place.

(x, y) ---> (y, x)

Therefore, if C = (-5,-6) then C' = (-6, -5).

Step-by-step explanation:

When you reflect a point (x, y) across the line y = x, the coordinates get interchanged. Thus,

(a,b) ⟶ (b,a)

Here are the coordinates of your triangle before and after the reflection.

The diagram below shows ∆ABC with its reflection ∆A'B'C'.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

step-by-step explanation:

what is the figure? attach a picture.