(if f(x)=4x^2 and g(x)=x+1, find (f o g)(x)

f(g(x)) = x² + 2x +1

Step-by-step explanation:

The given functions are:

f(x) = 4x²

g(x) = x+1

 f(x) = 4x²

(fog)(x) = f(g(x))

f(g(x)) = 4(x+1)²                 [f(x) = x² ]

 we know that (a+b)² = a² + b² + 2ab

f(g(x))  = 4(x²+1²+2(x)(1))

f(g(x))  = 4(x² + 1 + 2x )

f(g(x)) = 4x² + 8x +4

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent