How can a regular hexagon be folded to show that it has reflectional symmetry?
fold the hexagon along a line from a vertex to the midpoint of an opposite side.
fold the hexagon along a line connecting the two midpoints of adjacent sides
fold the hexagon along a line that bisects two vertex angles.
fold the hexagon along a line that creates a right angle at a vertex

The figure below shows a line graph and two shaded triangles that are similar:

Step-by-step explanation:

it will fold and look the same

c. Fold the hexagon along a line that bisects two vertex angles.

Step-by-step explanation:

Reflectional symmetry also means the mirror symmetry. This occurs when a shape is divided by a line in halves, and each half is a reflection of the other half.

So, the regular hexagon must be folded like the following way to show that it has reflectional symmetry -

Fold the hexagon along a line that bisects two vertex angles.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: