Find the angle between u = (8.- 3) and v = (-3,- 8) round to the nearest tenth of a degree.
a. 180
c. 0
b. 90
d. 450

Step-by-step explanation:

First you must calculate the module or the magnitude of both vectors

The module of u is:

The module of v is:

Now we calculate the scalar product between both vectors

Finally we know that the scalar product of two vectors is equal to:

Where is the angle between the vectors u and v. Now we solve the equation for

the answer is 90°

Whenever the scalar product of two vectors is equals to zero it means that the angle between them is 90 °

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft