Identify an equation in point-slope form for the line perpendicular to y = -1/3x - 6 that passes through (-1, 5). a. y + 1 = 3(x - 5) b. y + 5 = 1/3(x - 1) c. y - 5 = -1/3(x + 1) d. y - 5 =3(x + 1)

D. y - 5 =3(x + 1)

Step-by-step explanation:

y = -1/3x -6

The slope is -1/3

Take the negative reciprocal to find the slope of the line that is perpendicular

- (-3) = 3

The slope would be 3

We have the slope and a point

Using point slope form

y-y1 = m(x-x21)

y-5 = 3(x--1)

y-5 = 3(x+1)

D. y - 5 =3(x + 1)

Step-by-step explanation:

Given equation of line:

Comparing it with the standard form of equation of line

y=mx+b

m = -1/3

Let m1 be the slope of line perpendicular to the given line.

We know that the product of slopes of two perpendicular lines is -1.

The equation of line in point slope form is:

where x_1 and y_1 is the point from which the line passes.

So, putting the values of slope and point,

Option D is correct ..

answer: 1 and 3

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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