The sum of eli’s age and cecil’s age is 60. six years ago, eli was three times old as cecil. find eli’s age now

Eli's age = 42 years

Step-by-step explanation:

Let x be Eli's age and y be Cecil's age

So,

According to the statement given

x+y=60     eqn 1

Eli's age 6 years ago = x-6

Cecil's age 6 years ago = y-6

So according to the given statement

x-6 = 3(y-6)

x-6 = 3y - 18

x-3y = -18+6

x-3y= -12      eqn 2

Subtracting eqn 2 from eqn 1

x+y - (x-3y) = 60 - (-12)

x+y-x+3y = 60+12

4y = 72

y = 18

Cecil's age = 18 years

Putting y = 18 in eqn 1

x+18=60

x = 60-18

x = 42

Eli's age = 42 years ..

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

range is infinite on both x and y axis positive and negative

step-by-step explanation: