It is known that for all tests administered last year, the distribution of scores was approximately normal with mean 74 and standard deviation 7.1. a. a particular employer requires job candidates to score at least 80 on the dexterity test. approximately what percentage of the test scores during the past year exceeded 80?

19.77%

Step-by-step explanation:

Given: Mean :

Standard deviation :

The formula to calculate z-score is given by :_

For x= 80, we have

The P-value =

In percent ,

Hence, the approximate percentage of the test scores during the past year exceeded 80 =19.77%

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

step-by-step explanation: