What is the product?

(x − 3)(2x2 − 5x + 1)

2x3 − x2 + 16x + 3
2x3 − 11x2 + 16x + 3
2x3 − 11x2 + 16x − 3
2x3 − x2 + 16x − 3

Third option: 2x^3-11x^2+16x-3

Step-by-step explanation:

The product to be found is:

Distributive property will be used for the product:

Multiplication will give us:

The product is: 2x^3-11x^2+16x-3

Hence, third option is the correct answer ..

The product is 2x³ - 11x² + 16x - 3 ⇒ 3rd answer

Step-by-step explanation:

* Lets explain how to find the product of binomial by trinomial

- If (ax² ± bx ± c) and (dx ± e) are trinomial and binomial, where

 a , b , c , d , e  are constant, their product is:

# Multiply (ax²) by (dx) ⇒ 1st term in the trinomial and 1st term in the  

 binomial

# Multiply (ax²) by (e) ⇒ 1st term in the trinomial and 2nd term in

the binomial

# Multiply (bx) by (dx) ⇒ 2nd term the trinomial and 1st term in  

the binomial

# Multiply (bx) by (e) ⇒ 2nd term in the trinomial and 2nd term in    the binomial

# Multiply (c) by (dx) ⇒ 3rd term in the trinomial and 1st term in  

 the binomial

# Multiply (c) by (e) ⇒ 3rd term the trinomial and 2nd term in  

the binomial

# (ax² ± bx ± c)(dx ± e) = adx³ ± aex² ± bdx² ± bex ± cdx ± ce

- Add the terms aex² and bdx² because they are like terms

- Add the terms bex and cdx because they are like terms

* Now lets solve the problem

∵ The binomial is (x - 3) and the trinomial is (2x² - 5x + 1)

∴ (x)(2x²) = 2x³

∵ (x)(-5x) = -5x²

∵ (x)(1) = x

∵ (-3)(2x²) = -6x²

∵ (-3)(-5x) = 15x

∵ (-3)(1) = -3

∴ (x - 3)(2x² - 5x + 1) = 2x³ + -5x² + x + -6x² + 15x + -3

- Add the like terms

∵ -5x² and -6x² are like term

∴ Their sum is -11x²

∵ x and 15 x are like terms

∴ Their sum = 16x

∴ (x - 3)(2x² - 5x + 1) = 2x³ - 11x² + 16x - 3

* The product is 2x³ - 11x² + 16x - 3

step-by-step explanation: the answer for wha if rt is 10 centimeters long, and wha is st? it’s 6

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!