Ireally need on question 22, can anyone me? !

First, we need to find the missing side which is BC ( using pythagorean theorem)

AB² + BC² = AC²

=> 16² + BC² = 20²

=> BC²          = 20² - 16² = 144

=> BC           = √144 = 12

Now apply the formulars:

Just to make things easier, let's point out exactly what will the hypotenuse, opposite side and adjacent side.

So in this case:

The hypotenuse will be AC

The opposite side (of angle A) is BC

The adjacent side (of angle A) is AB

Therefore:

sin A = opposite/hypotenuse = BC/AC = 12/20 = 3/5

cos A = adjacent/hypotenuse = AB/AC = 16/20 = 4/5

tan A = opposite/adjacent = BC/AB = 12/16 = 3/4

ab: 2 n83b8eb7ebi. 8e yen in