Atest score of 48.4 on a test having a mean of 66 and a standard deviation of 11. find the z-score corresponding to the given value and use the z-score to determine whether the value is significant. consider a score to be significant if its z-score is less than -2.00 or greater than 2.00. round the z-score to the nearest tenth if necessary. a. -1.6; not significant b.-17.6; significant c. -1.6, significant d. 1.6; not significant

A. -1.6; not significant

Step-by-step explanation:

The z-score of a data set that is normally distributed with a mean of and a standard deviation of , is given by:

.

From the question, the test score is: , the mean is , and the standard deviation is .

We just have to plug these values into the above formula to obtain:

.

This simplifies to:  .

.

We can see that the z-score falls within two standard deviations of the mean.

Since the value is not significant.

The correct answer is A. -1.6; not significant