Arectangle has vertices at (-2, 11), (-2, 4), (6, 11), and (6, 4). pablo says te area of the rectangle is 49 square units and his work is shown below. step 1. base: |-2|+|6|=8 step 2. height: 11-4=7 step 3. area: 8x7=49 square units. where, if at all, did pablo make his first mistake finding the area of the rectangle?

The error is in the Step 3

Step-by-step explanation:

we know that

The area of a rectangle is equal to

A=bh

where

b is the base of rectangle

h is the height of rectangle

so

The Step 1 calculating the  Base is correct

The Step 2 calculating the Height is correct

The Step 3 calculating the area of rectangle is not correct

because

A=(8)(7)=56 units² instead of 49 units²

33

step-by-step explanation: g=6

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.