Geometry - - will mark brainliest
1. are the following slopes parallel, perpendicular or neither?
y = -1/3x + 2
y = 3x - 5
2. how are squares and rhombi different?
3. find the slope and distance between these two points.
a(0,11)
b(-5,2)

see below

Step-by-step explanation:

1.  y = mx+b where m is the slope

The first slope is -1/3

The second slope is 3

m1 = m2 means they are parallel  False

m1*m2 = -1  means they are perpendicular

-1/3 *3 = -1  True

2.  Squares and rhombi have all 4 sides with the same length.  Squares however, have 4 angles that must equal 90 degrees.  Squares are a special form of rhombi

3.  To find the slope

m = (y2-y1)/(x2-x1)

   = (2-11)/(-5-0)

   =-9/-5

   = 9/5

The distance is found by

d = sqrt( (x2-x1)^2 + (y2-y1)^2)

  = sqrt( (-5-0)^2 + (2-11)^2)

  = sqrt( 5^2 + (-9)^2)

  = sqrt( 25+81)

  = sqrt( 106)

See below

Step-by-step explanation:

y = -1/3x + 2

y = 3x - 5

Slopes are -1/3 and 3, they are opposite-reciprocal, it means the lines are perpendicular

2. Difference between squares and rhombus:

3. points A(0,11)  and B(-5,2)

Slope:

m= (y2-y1)/(x2-x1)= (2-11)/(-5-0)= -11/-5= 11/5

Distance between points:

√(x2-x1)²+(y2-y1)²= √ 25+121= √146 ≈ 12

the answer is a

step-by-step explanation:

what is the original number? you forgot to add it.