The value 3 is an upper bound for the zeros of the function shown below f(x)=-3x^3+2x^2-36x+16

For the quadratic function [tex]y=(x+4)^2-1[/tex] , do the following: a) rewrite the function in the standard form, b) rewrite the function in intercept form, c) find the vertex, d) find the y-intercept, e) find the x-intercepts.

Ab and bc are tangent to circle d. find x is ab = 3x + 8 and bc = 26. find x

(a.s."similarity in right triangles"solve for xa.) 10b.) 20c.) 14.5d.) [tex] 6\sqrt{3} [/tex]