The sum of the measures of two complementary angles exceeds the difference of their measures by 72°. find the measure of the smaller angle

Complementary angles are pair of two non-right angles whose sum is equal to 90°

Let the two complementary angles be : Δ and Ф

Given : Sum of the measures of two complementary angles exceed the difference of their measures by 72°

 Δ + Ф - 72° = Δ - Ф

 2Ф = 72°

 Ф = 36°

As Δ and Ф are complementary, their sum should be equal to 90°

 Δ + 36° = 90°

 Δ = 90° - 36°

 Δ = 54°

So, Complementary angles are 54° and 36°

Answer : The Measure of the Smaller Angle is 36°

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )