The point-slope form of the equation of the line that passes through (-5, -1) and (10,-7) is
y+7=-(x-10). what is the
standard form of the equation for this line?
2x-5y = -15
2-5y=-17
2x+6y=-15
2x+5v=-17

That should be 2x + 5y = 20.

Step-by-step explanation:

First, you have to correct this: y + 7 = -⅖(x - 10). Now, first convert to Slope-Intercept Form by moving -7 to the other side of the equivalence symbol to get y = -⅖x + 4, then finally convert to Standard Form by moving ⅖x to the other side of the equivalence symbol to end up with ⅖x + y = 4.. Now, there is an extended step when it comes to fractional coefficients, and that is multiplying the whole equation by the denominator to get rid of the denominator being there in the first place, REALLY ending with 2x + 5y = 20.

BUT, if your assignment says otherwise, then the first looks correct. I hope this helps.

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation