The equation of line cd is y = 3x − 3. write an equation of a line perpendicular to line cd in slope-intercept form that contains point (3, 1).
y = 3x + 0
y = 3x − 8
y = negative 1 over 3x + 2
y = negative 1 over 3x + 0

y = - x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 3 ← is in slope- intercept form

with m = 3

Given a line with slope m then the slope of a line perpendicular to it is

= - = - , thus

y = - x + c ← is the partial equation of the perpendicular line

To find c substitute (3, 1) into the partial equation

1 = - 1 + c ⇒ c = 1 + 1 = 2

y = - x + 2 ← equation of perpendicular line

y = negative 1 over 3x + 0

Step-by-step explanation:

Given equation of line is:

Comparing with the standard form

y=mx+b

The co-efficient of x is the slope of the line.

Let m1 be the slope of this line

So,

m1 = 3

We know that the product of slopes of perpendicular lines is -1.

Let m2 be the slope of second line

m1 * m2 = -1

3 * m1 = -1

To find the value of b, we have to put the point and slope in standard form

Hence, last option is correct ..

m1 = -1/3