Fill in the blank with a digit such that the resulting number is divisible by 11.
(a) 362,
(b) 82,
(c) 57,

Hence, a) 0,  b) 2, and  c) 0

Step-by-step explanation:

As we know that If the difference of sum of odd places values and sum of even places value is divisible by 11, then the number is itself divisible by 11.

(a) 362,375,__35

Sum of odd places values : 3+2+7+5+x=17+x

Sum of even places values : 6+3+5+3=17

Difference between them is 17+x-17=x

So, x should be 0 to get divisible by 11 as 0 is divisible by 11.

(b) 82,919,__21

Sum of odd places values : 8+9+9+2=28

Sum of even places values : 2+1+x+1=4+x

Difference between them is 28-(4-x)=24-x

So, x should be 2 so, that it becomes 24-2=22 which is divisible by 11.

(c) 57,13__,473

Sum of odd places values : 5+1+x+7=13+x

Sum of even places values : 7+3+4+3=17

Difference between them is 17-(13+x)=4-x

So, x should be 4 so that it becomes 4-4=0 which is divisible by 11.

Hence, a) 0,  b) 2, and  c) 0

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b