Genet multiplied a 3-digit number by 1002 and got ab007c, where a, b, and c stand for digits. what was genet's original 3-digit number?

  539

Step-by-step explanation:

The 007C requires the least significant two digits be in the range 35-39. In order for the 10-thousands digit to be zero, the sum of 1000 times the least digit of Genet's number and 2 times the hundreds digit must result in a sum with no thousands. About the only way to do that is to make the least digit 9 and the hundreds digit 5.

Then you have ...

  539 × 1002 = 540078 . . . . . ABC =548

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

1. 22

2. 1

3. 7

4. 18

step-by-step explanation

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