Apoint on the rim of a wheel moves with a velocity of 60 feet per second. find the angular velocity of the point if the diameter of the wheel is 6 feet. 10 rad/sec 20 rad/sec 180 rad/sec 360 rad/sec

20 rad/sec

Step-by-step explanation:

The formula we are going to use is  

Where

v is the linear velocity (here given 60 ft/s)

 is the angular velocity (what we sought to find)

r is the radius (which is half of diameter, hence, 6/3 = 3 ft)

Plugging these numbers in, we find the angular velocity as:

Note: the units is radians per second (rad/s)

Correct answer 20 rad/sec

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

okay..i will pick 8!