Abox contains 12 balls numbered 1 through 12. two balls are drawn in succession without replacement. if the second ball has the number 4 on it, what is the probability that the first ball had a smaller number on it? an even number on it? the probability that the first ball had a smaller number is nothing.

A box contains 12 balls numbered 1 through 12.

Also the ball are drawn without replacement.

a)

The probability that the first ball had a smaller number on it.

i.e. the number on the first ball could be: {1,2,3}

Hence, the probability  that the first ball had a smaller number on it is:

b)

The probability that the first ball has a even number on it is:

There are total 6 even numbers {2,4,6,8,10,12}

but 4 can't be considered as it comes on the second draw, so we are left with just 5 balls with even number.

Hence, the probability is:

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8