4. solve the equation 30a2 – 7 = 29a.

Value of a = 7/6 and a = -1/5

Step-by-step explanation:

We need to solve the equation

30a^2 -7 = 29a

Adding -29a on both sides

30a^2-29a-7=0

Solving the quadratic equation using quadratic formula.

here a= 30, b =-29 and c=-7

Putting values, and finding the value of a

So, value of a = 7/6 and a = -1/5

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)