Agraph of quadratic function y = f(x) is shown below.
what is the solution set of the quadratic inequality f(x) ≥ 0?

{f|0 ≤ f(x)}; x² - 4x + 5

Step-by-step explanation:

To find the Quadratic Equation, plug the vertex into the Vertex Equation FIRST, y = a(x - h)² + k, where (h, k) → (2, 1) is the vertex, plus, -h gives you the OPPOSITE terms of what they really are, and k gives you the EXACT terms of what they really are: (x - 2)² + 1. Doing this will give you the Quadratic Equation of x² - 4x + 5. You understand now?

I am joyous to assist you anytime.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!