Given sin theta = -3/5 and csc theta -5/3 in quadrant 3, find the value of other trigonometric functions using a pythagorean identity. show your work.

cos theta = -4/5.

sec theta = -5/4.

tan theta = 3/4.

cot theta = 4/3.

Step-by-step explanation:

sin^2 theta + cos^2 theta = 1

(-3/5)^2 + cos^2 theta = 1

cos^2 theta = 1 - 9/25

cos^2 theta = 16/25

cos theta = -4/5 (negative because  it is in Quadrant 3).

sec theta = 1 / cos theta = -5/4.

tan theta = sin theta / cos theta = -3/5 / - 4/5

= -3/5 * -5/4

=  3/4.

cot theta  =  1 / tan theta = 4/3.

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step-by-step explanation:

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all it means is function 3