![\large\boxed{n\leq9\ or\ n13\to n\in\left(-\infty;\ 9\right]\ \cup\ (13,\ \infty)\to\{x\ |\ x\leq9\ or\ x13\}}](/tpl/images/0041/6825/20c63.png)
![n-12\leq-3\ or\ 2n26\\\\n-12\leq-3\qquad\text{add 12 to both sides}\\n\leq9\\\\2n26\qquad\text{divide both sides by 2}\\n13\\\\n\leq9\ or\ n13\to n\in\left(-\infty;\ 9\right]\ \cup\ (13,\ \infty)\to\{x\ |\ x\leq9\ or\ x13\}](/tpl/images/0041/6825/9285a.png)
Solve the compound inequality.
n-12< =-3 or 2n> 26...
Answers: 1
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