Anormal distribution has a mean of 50 and standard deviation of 5. which value produces a negative z-score?

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Step-by-step explanation:

The z-score for a normal distribution is calculated using the formula:

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From the question, the distribution has a mean of 50.

and the standard deviation is .

For a z-score to be negative, then, .

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Any value less than 50 will produce a negative z-score

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

you have orange juice on wednesday. (idk why this is the answer)

step-by-step explanation: