Math 133a term test iv page 4 of 5 name: 4. application: discontinuous forced ivps consider an undamped pendulum weighting 1 kg and with a restoring force constant of 4 n/m. suppose we extend the pendulum 1 m to the right and give it an initial kick of 2 m/s to the right. suppose furthermore that there is a right-ward impulse applied to the pendulum at t 5 s. this gives rise to the follow model: [5) use the laplace transform method to determine the solution z(t) of (1). [note: l 12-6(1--l {? (t-5)) .]

answer: a

step-by-step explanation:

if xy ~ yz therefore xy would be the same length as yz

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s