Suppose you just received a shipment of thirteen televisions. three of the televisions are defective. if two televisions are randomly selected, compute the probability that both televisions work. what is the probability at least one of the two televisions does not work?

 0.4083

Step-by-step explanation:

Let D be the event of receiving a defective television.

Given : The probability that the television is defective :-

The formula for binomial distribution :-

If two televisions are randomly selected, compute the probability that both televisions work, then  the probability at least one of the two televisions does not work is given by :_

Hence , the required probability = 0.4083

the first dot plot best represents the data

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step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )