9. an rsa cryptosystem has modulus n 391, which is a product of the primes 23 and 17. which of the following is suitable as an encoding key e? (a) 163 (b) 353 (c) 351 (d) 277 (e) none of these. 10. which of the following polynomials p(x) is complete over zalr? (a) z4+1 (e) none of these

163

Step-by-step explanation:

So n=391.

This means p=23 and q=17 where p*q=n.

We want to choose e so that e is between 1 and 176 and the gcd(e,176)=1.

There is only one number in your list that is between 1 and 176... Hopefully the gcd(163,176)=1.

It does. See notes below for checking it:

176=2(88)=2(4*22)=2(2)(2)(2)(11)

None of the prime factors of 176 divide 163 so we are good.

The answer is 163.

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)

they are simplified

step-by-step explanation: