For each n = 1,2,3, define fn(x)x(1- t), for every e (-1,1]. let f : r2-r be defined by f(2, y)) = x2e 2 2y, for every (x, y) e r2. then the function fdefined by f(x): = lim fn(x) f(0,0)) + fm (0,0)) is: the value of f((0,0)) + noo exists for each x e [-1,1] and is equal to select one: select one: undefined f(x) 0 a = 1 -2 o 0 f(x)= 0 o a

F(x) = x2 − 9, and g(x) = x − 3 f(x) = x2 − 4x + 3, and g(x) = x − 3 f(x) = x2 + 4x − 5, and g(x) = x − 1 f(x) = x2 − 16, and g(x) = x − 4 h(x) = x + 5 arrowright h(x) = x + 3 arrowright h(x) = x + 4 arrowright h(x) = x − 1 arrowright

You were told that the amount of time lapsed between consecutive trades on the new york stock exchange followed a normal distribution with a mean of 15 seconds. you were also told that the probability that the time lapsed between two consecutive trades to fall between 16 to 17 seconds was 13%. the probability that the time lapsed between two consecutive trades would fall below 13 seconds was 7%. what is the probability that the time lapsed between two consecutive trades will be between 14 and 15 seconds?

Divide. write in simplest form 41/6 divided by 10