Acar dealership has 6 red, 9 silver, and 3 black cars on the lot. six cars are randomly chosen to be displayed in front of the dealership. find the probability that 3 cars are red and 3 are black. 0.001077 (round to six decimal places as needed.)

Hence, our required probability is 0.001077.

Step-by-step explanation:

Since we have given that

Number of red cars = 6

Number of silver cars = 9

Number of black cars = 3

Total number of cars = 6+9+3=18

We need to find the probability that 3 cars are red and 3 are black.

So, the required probability is given by

Hence, our required probability is 0.001077.

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.