Sin4θ - sin2θ =
2cos3θcosθ
2cos3θsinθ
2sin3θcosθ
2sin3θsinθ...
Mathematics, 05.07.2019 08:10 keenonwhite2612
Sin4θ - sin2θ =
2cos3θcosθ
2cos3θsinθ
2sin3θcosθ
2sin3θsinθ
Answers: 2
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