According to a survey by accountemps, 48% of executives believe that employees are most productive on tuesdays. suppose 200 executives are randomly surveyed.
a. what is the probability that fewer than 90 of the executives believe employees are most productive on tuesdays?
b. what is the probability that more than 100 of the executives believe employees are most productive on tuesdays?
c. what is the probability that more than 80 of the executives believe employees are most productive on tuesdays?

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

40 x 50 = 2000

step-by-step explanation:

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.

the answer would be a 24

step-by-step explanation:

c=2πr=2·π·3=24